(x-3)^2+5x=21

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Solution for (x-3)^2+5x=21 equation: 



(x-3)^2+5x=21

We move all terms to the left:

(x-3)^2+5x-(21)=0

We add all the numbers together, and all the variables

5x+(x-3)^2-21=0

We move all terms containing x to the left, all other terms to the right

5x+(x-3)^2=21

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